Haskell 習題 2.1:LISTS OF LISTS

1. rewrite the previous list literals using only (:) and the empty list constructor [].1(('a':[]):('b':[]):('c':[]):[]):(('d':[]):('e':[]):[]):[] 2. Write an expression that checks whether a list is e
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name

名字又代表了誰?我們把朵玫瑰取為別的名字,這朵花香味依舊。

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complex

簡單的事情諸如此類,於是乎我們讓某些變得複雜來困擾我們,老是這樣

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lancetw aka Hsin-lin Cheng